URI Online Judge Solution 1042 Simple Sort - Solution in C, C++, Java, Python and C# - Online Judge Solution

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Wednesday, July 12, 2017

URI Online Judge Solution 1042 Simple Sort - Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1042 Simple Sort - Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1042 | Beginner
URI Problem Link - https://www.urionlinejudge.com.br/judge/en/problems/view/1042

Problem Name: URI - Simple sort
Problem Number : URI - 1042
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Online Judge Solution 1042 Simple Sort - Solution in C, C++, Java, Python and C#


URI 1042 Simple Sort Code in C / URI 1042 solution in C:

#include <stdio.h>

void printInOrder(int a, int b, int c)
{
    int min, mid, max;
    if(a < b && a < c){
        min = a;
        if(b < c){
            mid = b;
            max = c;
        }else{
            mid = c;
            max = b;
        }
    }else if(b < a && b < c){
        min = b;
        if(a < c){
            mid = a;
            max = c;
        }else{
            mid = c;
            max = a;
        }
    }else{
        min = c;
        if(a < b){
            mid = a;
            max = b;
        }else{
            mid = b;
            max = a;
        }
    }
    printf("%d\n%d\n%d\n", min, mid, max);

}

int main()
{
    int a, b, c;

    scanf("%d %d %d", &a, &b, &c);

    printInOrder(a, b, c);
    printf("\n%d\n%d\n%d\n", a, b, c);

    return 0;
}


URI 1042 Simple Sort Code in C++ / URI 1042 solution in CPP:

#include <iostream>
using namespace std;

void printInOrder(int a, int b, int c)
{
    int min, mid, max;
    if(a < b && a < c){
        min = a;
        if(b < c){
            mid = b;
            max = c;
        }else{
            mid = c;
            max = b;
        }
    }else if(b < a && b < c){
        min = b;
        if(a < c){
            mid = a;
            max = c;
        }else{
            mid = c;
            max = a;
        }
    }else{
        min = c;
        if(a < b){
            mid = a;
            max = b;
        }else{
            mid = b;
            max = a;
        }
    }

    cout << min << endl << mid << endl << max << endl << endl;
        
}

int main()
{
    int a, b, c;

    cin >> a >> b >> c;

    printInOrder(a, b, c);

    cout << a << endl << b << endl << c << endl;

    return 0;
}


URI 1042 Simple Sort Code in java/ URI 1042 solution in Java:

import java.io.IOException;
import java.util.Scanner;
 
public class Main {
 
    public static void main(String[] args) throws IOException {
 
       
  int X, Y, Z, min1, min2 = 0, min3 = 0;
  Scanner input = new Scanner(System.in);
  X = input.nextInt();
  Y = input.nextInt();
  Z = input.nextInt();
  min1 = Math.min(X, Math.min(Y, Z));
  if (min1 == X) {
   min2 =Math.min(Y, Z);
   min3 =Math.max(Y, Z);
  }
  if (min1 == Y) {
   min2 =Math.min(X, Z);
   min3 =Math.max(X, Z);
  }
  if (min1 == Z) {
   min2 = Math.min(X, Y);
   min3 = Math.max(X, Y);
  }
  System.out.print(min1+"\n"+min2+"\n"+min3+"\n\n");
  System.out.print(X+"\n"+Y+"\n"+Z+"\n");
 
    }
 
}


URI 1042 Simple Sort Code in Python / URI 1042 solution in Python:

# -*- coding: utf-8 -*-
#Pegando os números do teclado
entrada = raw_input().split()
#Transformando eles em inteiro
a = int(entrada[0])
b = int(entrada[1])
c = int(entrada[2])

#Colocando todos em uma lista
lista = [a,b,c]

#Ordenando a lista
lista.sort()

#Mostrando os numeros ordenados
print lista[0]
print lista[1]
print lista[2]
print ""

#Mostrando os números como foram digitados
print a
print b
print c


URI Solution 1042 Simple Sort Code / URI 1042 solution in  C# (C Sharp):




Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks



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1 comment:

  1. This is for the python:

    x,y,z =list(map(float,input().split()))
    list = [x,y,z]
    list.sort()
    print("%d\n%d\n%d"%(list[0],list[1],list[2]))
    print("\n%d\n%d\n%d"%(x,y,z))

    ReplyDelete