URI Online Judge Solution 1035 Selection Test 1 - URI 1035 Solution in C, C++, Java, Python and C#
URI Online Judge Solution 1035 Selection Test 1 | BeginnerURI Problem Link - https://www.urionlinejudge.com.br/judge/en/problems/view/1035
Problem Name: 1035 Selection Test 1 code
Problem Number : URI - 1035 Selection Test 1 solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)
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| URI Online Judge Solution 1035 Selection Test 1 - URI 1035 Solution in C, C++, Java, Python and C# |
URI Solution 1035 Selection Test 1 Code in C / URI 1035 code in C:
#include <stdio.h> int main() { int a, b, c, d; scanf("%d %d %d %d", &a, &b, &c, &d); if((b > c) && (d > a) && (c + d > a + b) && c > 0 && c > 0 && (a % 2 == 0)) printf("Valores aceitos\n"); else printf("Valores nao aceitos\n"); return 0; }
URI Solution 1035 Selection Test 1 Code / URI 1035 Selection Test 1 solution in CPP:
Dynamic system:
#include <cstdio> #define SC4(a, b, c, d) scanf("%d %d %d %d", &a, &b, &c, &d) using namespace std; int main(int argc, char const *argv[]) { int a, b, c, d; SC4(a, b, c, d); if((b > c) && (d > a) && (c + d > a + b) && c > 0 && c > 0 && (a % 2 == 0)) puts("Valores aceitos"); else puts("Valores nao aceitos"); return 0; }
URI Solution 1035 Code / URI 1035 solution in Java:
import java.util.Scanner; public class Main { public static void main(String[] args) { int a, b, c, d; Scanner sc = new Scanner(System.in); a = sc.nextInt(); b = sc.nextInt(); c = sc.nextInt(); d = sc.nextInt(); if((b > c) && (d > a) && (c + d > a + b) && c > 0 && c > 0 && (a % 2 == 0)) System.out.printf("Valores aceitos\n"); else System.out.printf("Valores nao aceitos\n"); } }
URI Solution 1035 Code / URI 1035 solution in Python:
URI Solution 1035 Code / URI 1035 solution in C# (C Sharp):
Demonstration:
Just implement this in coding. Since having any problem just put a comment below. Thanks
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![Maniruzzaman Akash](https://i.ibb.co/qMzPWBW/IMG-0170-1-3-Copy.jpg" alt="AKASH-CV-2 "Maniruzzaman Akash")
int A,B,C,D;
ReplyDeletescanf("%d%d%d%d", &A,&B,&C,&D);
if((B > C && D > A) && (C + D > A + B) && (C > 0 && D > 0 )&& (A % 2 == 0))
{
printf("Valores aceitos\n");
}
else
printf("Valores nao aceitos\n");
/*
ReplyDelete#URI 2926 solutin by
Rifat Tangir
cse,Bangabandhu Sheikh Mujibur Rahaman Science & Technology
*/
#include
using namespace std;
int main()
{
int n,i;
cin>>n;
cout<<"Ent";
for(i=1;i<=n;i++){
cout<<"a";
}
cout<<"o eh N" ;
for(i=1;i<=n;i++){
cout<<"a";
}
cout<<"t";
for(int i=0;i<n;i++){
cout<<"a";
}
cout<<"l!"<<endl;
}
#include
ReplyDeleteint main()
{
int A,B,C,D;
scanf("%d %d %d %d",&A,&B,&C,&D);
int sum=C+D;
int sum1=A+B;
if(B>C && D>A && sum>sum1 && C>0 && D>0 && (A%2==0))
{
printf("Valores aceitos\n");
}
else
printf("Valores nao aceitos");
}