URI Online Judge Solution 1073 Even Square - Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1073 Even Square - Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1073 Even Square | Beginner
URI Problem Link - https://www.urionlinejudge.com.br/judge/en/problems/view/1073

Problem Name: 1073 Even Square
Problem Number : URI - 1073 Even Square
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Solution 1073 Even Square Code in C:

#include <stdio.h>
int main()
{
 int n, i;

 scanf("%d", &n);

 for ( i = 1; i <= n; ++i)
 {
  if(i % 2 == 0){
   printf("%d^2 = %d\n", i,(i * i));
  }
 }

 return 0;
}

URI Solution 1073 Even Square Code / URI 1002 solution in CPP:

#include <iostream>
 
using namespace std;
 
int main(int argc, const char * argv[])
{
    int N, i;
    
    cin >> N;

    for(i = 1; i <= N; i++) {
        if(i%2 == 0) {
            cout << i << "^2 = " << i*i << endl;
        }
    }
 
    return 0;
}

URI Solution 1073 Code / URI 1073 Even Square  solution in Java:

/**
    6  
    2^2 = 4
    4^2 = 16
    6^2 = 36

 */
import java.util.Scanner;
import java.io.IOException;

public class Main {

 public static void main(String[] args) {
  
  int N;
  Scanner input =new Scanner(System.in);
  N =input.nextInt();
  
  
  for (int i = 2; i <= N; i+= 2) {
   System.out.print(i+"^2 = "+(i*i)+"\n");
  }

 }

}

URI Solution 1073 Even Square Code / URI 1073 solution in  Python:

a=int(input())
for n in range(1,(a+1)):
    if (n%2==0):
        print("%d^2 = %d" %(n, n**2))

URI Solution 1073Code / URI 1073 Even Square solution in  C# (C Sharp):

Demonstration:

1. Take a loop upto n
2. Inside loop if that is divisble by 2 then
3. square it and print it. Main Lines are this-

 for ( i = 1; i <= n; ++i)
 {
  if(i % 2 == 0){
   printf("%d^2 = %d\n", i,(i * i));
  }
 }

Just implement this in coding. Since having any problem just put a comment below. Thanks



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