URI Online Judge | 1079 Weighted Averages - Solution in C, C++, Java, Python and C#

URI Online Judge | 1079 Weighted Averages - Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1079 Weighted Averages  | Beginner
URI Problem Link - https://www.urionlinejudge.com.br/judge/en/problems/view/1079

Problem Name: 1079 Weighted Averages
Problem Number : URI - 1079 Weighted Averages
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Solution 1079 Weighted Averages Code in C:

#include <stdio.h>

int main()
{
 int n;
 double a;
 double b;
 double c;

 scanf("%i", &n);

 for (int i = 0; i < n; ++i)
 {
  scanf("%lf", &a);
  scanf("%lf", &b);
  scanf("%lf", &c);

  double med = ((a/10) * 2) + ((b/10) * 3) + ((c/10) * 5);

  printf("%.1f\n", med);
 }

 return 0;
}

URI Solution 1079 Weighted Averages Code / URI 1079 Weighted Averages solution in CPP:

#include <cstdio>

int main()
{
 int n;
 double a;
 double b;
 double c;

 scanf("%i", &n);

 for (int i = 0; i < n; ++i)
 {
  scanf("%lf", &a);
  scanf("%lf", &b);
  scanf("%lf", &c);

  double med = ((a/10) * 2) + ((b/10) * 3) + ((c/10) * 5);

  printf("%.1f\n", med);
 }

 return 0;
}

URI Solution 1079 Weighted Averages Code / URI 1079 Weighted Averages solution in Java:

import java.util.Scanner;

public class Main {

 public static void main(String[] args) {
  
  int N;
  float value1, value2, value3;
  float average;
  Scanner input =new Scanner(System.in);
  N = input.nextInt();
  
  for (int i = 1; i <= N; i++) {
   value1 = input.nextFloat();
   value2 = input.nextFloat();
   value3 = input.nextFloat();
   average = ( value1*2 + value2*3 + value3*5 ) / 10;
   System.out.printf("%.1f\n", average);
  }
 }

}

URI Solution 1079 Weighted Averages Code / URI 1079 Weighted Averages solution in  Python:

URI Solution 1079 Weighted Averages Code / URI 1079 Weighted Averages solution in  C# (C Sharp):

Demonstration:

Just implement this in coding. Since having any problem just put a comment below. Thanks



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