URI Online Judge Solution 1010 Simple Calculate - URI 1010 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1010 Simple Calculate - URI 1010 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1010 Simple Calculate | Beginner
URI Problem Link - https://www.urionlinejudge.com.br/judge/en/problems/view/1010

Problem Name: 1010 Simple Calculate code
Problem Number : URI - 1010 Simple Calculate solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)

URI Solution 1010 Simple Calculate Code/ URI 1010 solution in C:

Simple sense URI 1010 code in C without array

#include <stdio.h>

int main()
{
 int a, b;
 double c, res;

 scanf("%d %d %lf", &a, &b, &c);
 res = b * c;
 scanf("%d %d %lf", &a, &b, &c);
 res += b * c;
 printf("VALOR A PAGAR: R$ %.2lf\n", res);

 return 0;
}

URI 1010 code in C with array

#include<stdio.h>
int main()
{
    int p_code[2], p_u[2], i;
    float price[2], pay;
    for(i=0; i<2; i++)
    {
        scanf("%d %d %f",&p_code[i],&p_u[i],&price[i]);
    }
    pay=((price[0]*p_u[0])+(price[1]*p_u[1]));
    printf("VALOR A PAGAR: R$ %.2f\n", pay);
    return 0;
 
}

URI Solution 1010 Simple Calculate Code / URI 1010 Simple Calculate solution in CPP:

#include <cstdio>
using namespace std;

int main(int argc, char const *argv[])
{
 int a, b;
 double c, res;

 scanf("%d %d %lf", &a, &b, &c);
 res = b * c;
 scanf("%d %d %lf", &a, &b, &c);
 res += b * c;
 printf("VALOR A PAGAR: R$ %.2lf\n", res);

 return 0;
}

URI Solution 1010 Simple Calculate Code / URI 1010 Simple Calculate solution in Java:

import java.util.Scanner;


public class Main{

 public static void main(String[] args) {
  
  int a, b;
  double c, res;
  Scanner sc = new Scanner(System.in);
  
  a = sc.nextInt();
  b = sc.nextInt();
  c = sc.nextDouble();
  res = b * c;
  
  a = sc.nextInt();
  b = sc.nextInt();
  c = sc.nextDouble();
  res += b * c;
  System.out.printf("VALOR A PAGAR: R$ %.2f\n", res);
  
  
 }

}

URI Solution 1010 Code / URI 1010 solution in  Python:

linha1 = input().split(" ")
linha2 = input().split(" ")

cod1, qtde1, valor1 = linha1
cod2, qtde2, valor2 = linha2

total = (int(qtde1) * float(valor1)) + (int(qtde2) * float(valor2))

print("VALOR A PAGAR: R$ %0.2f" %total)

URI Solution 1010 Code / URI 1010 solution in  C# (C Sharp):

URI Online Judge Solution 1010 Code Demonstration:

First take 3 values in store it in a result variable
Again take 3 value and now just increment the result variable. And solved, in C that is

        scanf("%d %d %lf", &a, &b, &c);
 res = b * c;
 scanf("%d %d %lf", &a, &b, &c);
 res += b * c;

Just implement this in coding. Since having any problem just put a comment below. Thanks



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