LightOj 1000 - Greetings from LightOJ - Solution in C

LightOj 1000 - Greetings from LightOJ - Solution in C

LightOJ Online Judge Solution 1000 | Beginner
LightOj Problem Link - http://www.lightoj.com/volume_showproblem.php?problem=1000

Problem Name: 1000 Greetings from LightOJ
Problem Number : LightOj- 1000
Online Judge : LightOj Online Judge Solution
Category: Beginner
Solution Language : C

LightOj Online Judge Solution 1000 Code in C:

#include <stdio.h>
 
int main() {
   int n, i = 1, x, y;
   scanf("%d", &n);
   
   while(n){
       scanf("%d%d", &x,&y);
       printf("Case %d: %d\n", i, x+y);
       i++;
       n--;
   }
   
   return 0;
}

Demonstration:

Take a variable for number of test case - n

   scanf("%d", &n);

Then Make a while loop upto that number. Then again take two values and print that just adding the values.

int n, i = 1, x, y;

while(n){
       scanf("%d%d", &x,&y);
       printf("Case %d: %d\n", i, x+y);
       i++;
       n--;
   }

Increment i and decrements n. i for print the case no.

Run LightOj 1000 code live and test the result:

Tags: LightOj Online Judge Solution, LightOj - Beginner