HackerRank Programming - Looping and Skipping - Bash Tutorials Solution

Hackerrank

Problem:

Looping and Skipping in Bash Programming.

Output Format

1
3
5
.
.
.
.
.
99 

Solution in Bash Programming Language:

#!/bin/bash
for i in {1..99..2};
do 
    echo $i;
done

Explanation:
So go to our code. In this line,

for i in {1..99..2};

We take a simple for loop that will go 1 to 99 and that will do two increment.

1. 1 is first value of i
2. 99 is the last value of i
3. 2 is the increments of i

That's the code. Then just echo or print the i variable. In Bash the variable is printed a dollar sign first, $.
The for loop is completed by done text.


Tags:
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