URI Online Judge Solution 1009 Salary with Bonus - URI 1009 Solution in C, C++, Java, Python and C#
URI Online Judge Solution 1009 Salary with Bonus | BeginnerURI Problem Link - https://www.urionlinejudge.com.br/judge/en/problems/view/1009
Problem Name: 1009 Salary with Bonus Code
Problem Number : URI - 1009 Salary with Bonus Solution
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)
URI Solution 1009 Salary with Bonus Code in C:
#include<stdio.h> int main() { double salary,value, TOTAL; char name; scanf("%s %lf %lf",&name,&salary,&value); TOTAL = salary+value*.15; printf("TOTAL = R$ %.2lf\n",TOTAL); return 0; }
URI Solution 1009 Salary with Bonus Code / URI 1009 Salary with Bonus solution in CPP:
#include <cstdio> int main() { double a; double b; char word[256]; scanf("%s", &word); scanf("%lf", &a); scanf("%lf", &b); printf("TOTAL = R$ %.2lf\n", a + ((b/100)*15)); return 0; }
URI Solution 1009 Code in Java/ URI 1009 solution in Java:
import java.util.Scanner; public class Main { public static void main(String[] args) { double salary = 0,value, TOTAL; String name; Scanner sc = new Scanner(System.in); name = sc.next(); salary = sc.nextDouble(); value = sc.nextDouble(); TOTAL = salary + value * 0.15; System.out.printf("TOTAL = R$ %.2f\n",TOTAL); } }
URI Solution 1009 Code / URI 1009 solution in Python:
nome = input() salfixo = float(input()) qtdevendas = float(input()) bonus = float(qtdevendas * (15/100)) total = salfixo + bonus print("TOTAL = R$ %0.2f" %total)
URI Solution 1009 Code / URI 1009 solution in C# (C Sharp):
Demonstration:
seller receives 15% over all products sold is in the problem and so multiply the result like this .15
TOTAL = salary + value * 0.15;
Just implement this in coding. Since having any problem just put a comment below. Thanks
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In C#
ReplyDeletestatic void Main(string[] args)
{
double A, B, Total;
string N = Convert.ToString(Console.ReadLine());
A = Convert.ToDouble(Console.ReadLine());
B = Convert.ToDouble(Console.ReadLine());
Total = A + B *0.15;
Console.WriteLine("TOTAL = R$ " + Total.ToString("0.00"));
Console.ReadLine();
}