UVA Solution 218 - Moth Eradication - Solution in C++ | Volume 2 - Online Judge Solution

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Sunday, April 30, 2017

UVA Solution 218 - Moth Eradication - Solution in C++ | Volume 2

UVA Solution 218 - Moth Eradication - Solution in C++ | Volume 2


UVA Online Judge Solution 120 - Moth Eradication| Volume 2
UVA Problem Link -

Problem Name: Moth Eradication 218
Problem Number : UVA - 218
Online Judge : UVA Online Judge Solution
Volume: 2
Solution Language : C plus plus

UVA Solution 218 Code in CPP:


#include <stdio.h>
#include <stdlib.h>
#include <math.h>
typedef struct {
 double x, y;
}Point;
Point P[100000], CH[100000];
int cmp(const void *i, const void *j) {
 Point *a, *b;
 a = (Point *)i, b = (Point *)j;
 if(a->x != b->x)
  return a->x - b->x > 0 ? 1 : -1;
 return a->y - b->y > 0 ? 1 : -1;
}
double cross(Point o, Point a, Point b) {
 return (a.x-o.x)*(b.y-o.y) - (a.y-o.y)*(b.x-o.x);
}
int montoneChain(int n) {
 qsort(P, n, sizeof(Point), cmp);
 int i, j, m = 0;
 for(i = 0; i < n; i++) {
  while(m >= 2 && cross(CH[m-2], CH[m-1], P[i]) >= 0)
   m--;
  CH[m++] = P[i];
 }
 for(i = n-1, j = m+1; i >= 0; i--) {
  while(m >= j && cross(CH[m-2], CH[m-1], P[i]) >= 0)
   m--;
  CH[m++] = P[i];
 }
 double length = 0;
 for(i = 0; i < m; i++) {
  if(i) {
   printf("-");
   length += sqrt((CH[i].x-CH[i-1].x)*(CH[i].x-CH[i-1].x) +
     (CH[i].y-CH[i-1].y)*(CH[i].y-CH[i-1].y));
  } 
  printf("(%.1lf,%.1lf)", CH[i].x, CH[i].y);
 }
 puts("");
 printf("Perimeter length = %.2lf\n", length);
}
int main() {
 int n, i, Case = 0;
 while(scanf("%d", &n) == 1 && n) {
  for(i = 0; i < n; i++)
   scanf("%lf %lf", &P[i].x, &P[i].y);
  if(Case) puts("");
  printf("Region #%d:\n", ++Case);
  montoneChain(n);
 }
    return 0;
}

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