URI Online Judge Solution 1011 Sphere - URI 1011 Solution in C, C++, Java, Python and C# - Online Judge Solution

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Wednesday, June 7, 2017

URI Online Judge Solution 1011 Sphere - URI 1011 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1011 Sphere - URI 1011 Solution in C, C++, Java, Python and C#

URI Online Judge Solution 1011 Sphere | Beginner
URI Problem Link - https://www.urionlinejudge.com.br/judge/en/problems/view/1011

Problem Name: 1011 Sphere solution
Problem Number : URI - 1011 Sphere code
Online Judge : URI Online Judge Solution
Category: Beginner
Solution Language : C,C plus plus, java, python, c#(c sharp)



URI Solution 1011 Sphere Code / URI 1011 solution in C:

URI 1011 as easy as possible:

#include <stdio.h>
#include <math.h>

int main()
{
 int a;

 scanf("%i", &a);
 printf("VOLUME = %.3lf\n", (4 * 3.14159 * pow(a, 3)) / 3);

 return 0;
}


URI 1011 Using Nice coding:

#include <stdio.h>
#include <math.h>
#define pi 3.14159
int main ()
{
    float r;
    while (scanf("%f",&r) != EOF)
    {
        printf("VOLUME = %.3f\n",(4/3.0)*pi*(r*r*r));
 
    }
    return 0;
 
}


URI Solution 1011 Sphere Code / URI 1011 Sphere solution in CPP:

#include <cstdio>
#include <cmath>

int main()
{
 int a;

 scanf("%i", &a);
 printf("VOLUME = %.3lf\n", (4 * 3.14159 * pow(a, 3)) / 3);

 return 0;
}


URI Solution 1011 Sphere Code / URI 1011 Sphere solution in Java:

import java.util.Scanner;


public class Main {

 public static void main(String[] args) {
  
  double a;
  Scanner sc = new Scanner(System.in);
  a = sc.nextDouble();
  
  System.out.printf("VOLUME = %.3f\n", (4 * 3.14159 * Math.pow(a, 3.0)) / 3);
  

 }

}



URI Solution 1011 Sphere Code / URI 1011 Sphere solution in  Python:

raio = int(input())

pi = 3.14159

volume = float(4.0 * pi * (raio* raio * raio) / 3)

print("VOLUME = %0.3f" %volume)


URI Solution 1011 Sphere Code / URI 1011 Sphere solution in  C# (C Sharp):


Demonstration:

It's pretty simple. The equation to solve URI 1011 is given (4/3) * pi * RJust in this line,

printf("VOLUME = %.3lf\n", (4 * 3.14159 * pow(a, 3)) / 3);


Just implement this in coding. Since having any problem just put a comment below. Thanks



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1 comment:


  1. In C#


    static void Main(string[] args)
    {
    double A ,Volume;

    A = Convert.ToDouble(Console.ReadLine());

    Volume = (4.0 / 3) * 3.14159 * (A * A * A);

    Console.WriteLine("VOLUME = " + Volume.ToString("0.000"));

    Console.ReadLine();


    }

    ReplyDelete